Use this to find the equation of the tangent line to the parabola y=3x 2 −5x+5 at the point (3,17) . The equation of this tangent line can be written in the form y=mx+b

1. What is (m) Slope?
2. What is (b) y-intercept ?

Question

Use this to find the equation of the tangent line to the parabola y=3x 2 −5x+5  at the point (3,17) . The equation of this tangent line can be written in the form y=mx+b

1. What is (m) Slope?
2. What is (b) y-intercept ?

anonymous · Answer

ok First thing to do is to find the derivative of $$3x^2 -5x + 5$$ Do you know how to do that?

anonymous · Answer

6x-5

anonymous · Answer

Excellent! Now plug in the x value of the point (3, 17) into $$6x - 5$$ and that is how you find the slope. So what do you get when you do that?

anonymous · Answer

13 !

anonymous · Answer

and then y intercept is -22 ! yayyyy

anonymous · Answer

Good. Now you have a slope of m = 13 and a point of (3,17). So using the point-slope formula which is $$y - y{1} = m(x - x{1})$$ plugging in those values you get $$y - 17 = 13(x - 3)$$ solve for y and that is the equation of the tangent line. so $$y = 13x - 22$$

anonymous · Answer

And you are correct! Nicely done!