Question

y=(4-x^2)(x^3-x+1) find y' both by multiplication and product rule

Answer 1

really? myininaya, which one do you want?

Answer 2

\[\ln(y)=\ln[(4-x^2)(x^3-x+1)]\]
i want the easy way lol

Answer 3

give me a break

Answer 4

ok you choose what way you want i will do the other

Answer 5

\[y=-x^5+5 x^3-x^2-4 x+4\]
\[y'=-5x^4+15x^2-2x-4\]

Answer 6

\[y'=(4-x^2)'(x^3-x+1)+(4-x^2)(x^3-x+1)' \]
\[=(0-2x)(x^3-x+1)+(4-x^2)(3x^2-1+0) \]

Answer 7

hmmm i wonder if they are the same...

Answer 8

\[=-2x(x^3-x+1)+(4-x^2)(3x^2-1)\]

Answer 9

\[=-5x^4+15x^2-2x-4\]

Answer 10

yes they are

Answer 11

\[-2x^4+2x^2-2x+12x^2-4-3x^4+x^2=x^4(-2-3)+x^2(2+12+1)-2x-4\]

Answer 12

\[=-5x^4+15x^2-2x-4\]