Question

sqrt2x^2+sqrt3x+1=0
use the discriminant to determin how many real roots each equation

Answer 1

that is not even right!

Answer 2

\[b^2-4ac=\sqrt{3}^2-4\times \sqrt{2}\times 1=3-4\sqrt{2}\]

Answer 3

\[b^2-4ac=(\sqrt{3})^2-4(\sqrt{2})(1)=3-4\sqrt{2}\]

Answer 4

ok is this the answer. This is what I I wrote for the equation

Answer 5

I guess i am confused

Answer 6

no real roots the discriminant is <0

Answer 7

you job is to see if this number is positive, negative or zero. it is negative (easy check) so not real solutions

Answer 8

>0=> two real roots
=0=> one real root (multiplicity 2)
<0=> no real roots

Answer 9

Thank you