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What is the square root of x^2+4x+4?
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\[\sqrt{ x^2+4x+4}\]
exactly
x+2
Technically correct, the best kind of correct.
+or -
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So there is no way to simplify?
There is, honeyboyseab is correct. It is plus or minus x+2
x^2+4x+4 factors to (x+2)^2
yes the terms under the square root sign is a perfect square and resolves to (x+2)^2 and the square root of that is (x+2)
Ah, I see now. Thanks!
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we have to break this function as...x^2+4x+4 we can write it like..x^2+2x+2x+4 now, we can take some common term here x(x+2)+2(x+2) Now again take common term here (x+2)(x+2)=(x+2)^2
and sqrt of(x+2)^2=x+2
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