Having trouble with this one as well..
27^{x}/9^{2x-1} = 3^{x+4}

I came up with:
3^{3x}/3^{2(2x-1)} = 3^{x+4}
3^{2(2x-1) -3x} = x+4
4x-2-3x = X+4
x-2 = x+4
and so on...but this is wrong and i'm not sure why. what did I do wrong?

Question

Having trouble with this one as well..
27^{x}/9^{2x-1} = 3^{x+4}

I came up with:
3^{3x}/3^{2(2x-1)} = 3^{x+4}
3^{2(2x-1) -3x} = x+4
4x-2-3x = X+4
x-2 = x+4
and so on...but this is wrong and i'm not sure why. what did I do wrong?

anonymous · Answer

$$\frac{3^{3x}}{3^{4x-2}} = 3^{x+4}$$

anonymous · Answer

$$\frac{3^{3x}}{3^{4x}}* 3^2=2^x * 3^4 $$

anonymous · Answer

$$3^{3x -4x} = 3^x * 3^2$$

anonymous · Answer

3^(3x)/3^(6x - 3) = 3^(x+4)
3^(3x-(6x-3)) = 3^(x+4)
3x-6x+3 = x + 4
-4x = 1
x = -0.5

look in your second row : you should have subtract the nominator from the denominator
also dont remove the basis from the right side before you do it on the left side.

anonymous · Answer

and its not -0.5 its -0.25 sorry

anonymous · Answer

it is $3^x$ not $2^x$ typo

anonymous · Answer

Ishaan, how did you write them as rationals, I cannot figure it out..

anonymous · Answer

on i was wrong again

anonymous · Answer

3^(3x)/3^(4x - 2) = 3^(x+4)
3^(3x-(4x-2)) = 3^(x+4)
3x-4x+2 = x + 4
-2x = 2
x = -1

anonymous · Answer

put 3^x  in \[ and \ ] (without space )

anonymous · Answer

actually correct syntax is 3^{x}

anonymous · Answer

or try it with equation editor