Question

16v^2-4v-20

Answer 1

4(4y^2 -y -5)
4(4y^2+4y -5y -5)
4(4y(y+1) -5(y+1))
4(4y-5)(y+1)

Answer 2

\[4(4y ^{2}-y-5)\]

Answer 3

4(4y-5)(y+1) so than y_1= -1 and y_2= 5/4

Answer 4

thanks