Question

PLEASE HELP PEEPS p(x)=4x^3-3x^2+bx+6

x-1 and x+3 are the factors. determine value of b when remainder is same for both factors!

Answer 1

the remainder is
\[p(1)\] and also
\[p(-3)\] find these, set the result equal, and solve for b

Answer 2

hope it is clear what i mean.

Answer 3

k so i got 7 and 43

Answer 4

hold on. your answer must have a b in it because you do not know what b is

Answer 5

for example,
\[p(1)=4-3+b+6=b+7\]

Answer 6

and
\[p(-3)=4\times (-3)^3-3\times (-3)^2-3b+6=-3b-129\] if my arithmetic is correct
that means
\[b+7=-3b+29\] and you can solve that for b

Answer 7

oh okokok thankyuverymuch goodsir

Answer 8

I think the calculation is not correct, however the procedure is perfect

\[b = -34\]

Answer 9

howyu get -34

Answer 10

typo on last line but again my calculation could be off
it should be
\[b+7=-3b-129\]
\[4b=-136\]
\[b=-34\] what alsamixer said

Answer 11

ok