can someone show me how to use the product rule to find(x^2+1)(X^2-2x)
sorry to diffferentation the function
Recall the product rule first of all\[dy/dx=f \prime(x)g(x)+f(x)g \prime(x)\]Let \[f(x)=x^2+1\]\[g(x)=x^2-2x\]Then we get\[f \prime(x)=2x\]\[g \prime(x)=2x-2\]Substitute these into the product rule formula\[dy/dx=2x(x^2-2x)+(x^2+1)(2x-2)\]Expand and simplify if necessary
well with the product rule you keep the first * the derivative of the second + keep the second * the derivative of the first.
thanks think i got it now
so you make them into derivivites as the first step all the time?
Yep, look for 2 functions that are multiplied together and set one of them as f(x) and the other as g(x). Find their derivatives and use the formula. Should work every time.
ooh got it now
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