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find limit as x approaches infinity. (5x^2+6)/(6x^2)
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\[\frac{5}{6}\] with your eyeballs
same power
numerator and denominator of are the same degree, so it is ratio of leading coefficients.
it would factor down to (5+6/x^2)/6 ?
looks like \[\frac{5}{6}\] if you do it with numbers. put x = 100 you get \[\frac{50000}{60006}\]
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ok so you just canceled out the 6/x^2?
thats in the numerator
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