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Differentiate y=e^x/x^2
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y'= ((xe^x) - (2e^x)) / x^3
i got \[[(xe ^{x})(x+2)]/x ^{4}\]
y' = [x^2(e^x) - e^x(2x)]/x^4 =[(e^x)(x^2-2x)]/x^4 =[x(e^x)(x-2)]/x^4 =[e^x(x-2)]/x^3
oh yea...you can cross out one of the x's and yea you should get what lgsallote got
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