Question

Please help. I've worked on this problem for two days :(

What are the vetices of the ellipse equation:
x^2 + 10x +4y^2-56y=-205

Answer 1

\[(9,7),(-1,7)\]

Answer 2

I think it should be (-9,7), (-1, 7)

Answer 3

yes you are right. i forgot the minus sign

Answer 4

first complete the square to get
\[(x+5)^2+4 (y-7)^2= 16\] then
\[\frac{(x+5)^2}{4}+(y-7)^2+4\]

Answer 5

\[\frac{(x+5)^2}{16}+\frac{(y-7)^2}{4}=1\] is what i am trying to write, dang

Answer 6

center at
\[(-5,7)\] and major axis is horizontal. (16 is bigger than 4) so add and subtract 4 from the x - value to get the vertices. that gives the answer

Answer 7

cooper, do you understand all those steps?

Answer 8

Yes....after several days of working! Ha!