Question

How do I solve log(x^2+5x+16)=1?

Answer 1

does the log have a base, or is it a natural log?

Answer 2

natural

Answer 3

then the equation will become x^2+5x+16 = e
(e means exponential). So you can solve this equation

Answer 4

if the base is 10 then the equation will become x^2+5x+16=10
so x=-2 0r x=-3

Answer 5

\[\ln (x^2+5x+16)=1\]
\[e ^{\ln x^2+5x+16 } = e ^{1}\]
\[x^2+ 5x + 16 = e\]
\[ x^2 + 5x = e/16\]
I dont know of any solutions to this. I mean, I dont know of any x that will end up giving you e/16...

Answer 6

Well you could try to shove it up your butt http://www.youtube.com/watch?v=ZGJDnFq6vno