Question

5x=3(mod7)

Answer 1

x = 3/5

Answer 2

5x-3=7k where k is some integer
x=2 is a solution

Answer 3

No agdgd: this is a problem in integers

Answer 4

x=3/5

Answer 5

oh I see.

Answer 6

http://en.wikipedia.org/wiki/Modular_arithmetic I get it.

Answer 7

if k=1 then 5x-3=7 =>x=2
if k=2 then 5x-3=14 => x=not integer
if k=3 then 5x-3=21 => x=not integer
if k=4 then 5x-3=28 => x=not integer
if k=5 then 5x-3=35 => x=not integer
if k=6 then 5x-3=42 => x=9
if k=7 then 5x-3=49 => x=not integer

Answer 8

so we could say x=2+7i for any integer i>=1

Answer 9

thank you.

Answer 10

i think there might be a shorter process
but i can't remember