The formula S = 16t^2 + v0t + s0 tells the height at time t of a projectile fired vertically from height s0 with initial velocity v0.
Suppose a projectile is fired vertically from ground level at an initial speed of 448 ft per second.
When will the projectile be higher than 3072 ft?

Question

The formula S = 16t^2 + v0t + s0 tells the height at time t of a projectile fired vertically from height s0 with initial velocity v0.
Suppose a projectile is fired vertically from ground level at an initial speed of 448 ft per second. 
When will the projectile be higher than 3072 ft?

anonymous · Answer

$$16 (t-16) (t-12)<0$$
$$12<t<16$$ continuing from last post
that is the answer you are looking for

anonymous · Answer

could you please explain it in detail... im not sure i would understand another question like this one >.< like how you got -16t^2 and how you made the 3072 go to the left and ended up with 0 on the right... please

anonymous · Answer

hey, i just checked this out, i would help but this is wayy to complicated for me. im only in the 1st stages of trig

anonymous · Answer

this equation has it accelerating up.  
S = -16t^2 + v0t + s0 makes it come back down