who knows 2 derieve the equation of motion"v^2=u^2+2as
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OpenStudy (anonymous):
i bet there arent many!!!!
OpenStudy (anonymous):
u guys fail 2 me hahhaha
OpenStudy (anonymous):
s=vt
v=u+v/2
s=((u+v)/2)/t--1
we know that v=u+at--2
plugging that in equation 1
s=[(u+u+at)/2]/t
s=[(2u+at)/2]/t
s=ut+1/2at^2--3
from equation 2
v^2=(u+at)^2
v^2=u^2+2uat+(at)^2
v^2=u^2+2a(ut+(1/2)at^2)
using equation 3 we have
v&2=u^2+2as
OpenStudy (anonymous):
hreat which grade r u???????
OpenStudy (anonymous):
v^2=u^2+2aS*
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OpenStudy (anonymous):
i know its physics
OpenStudy (anonymous):
Yh it is physics:)
OpenStudy (anonymous):
r u 12th????
OpenStudy (anonymous):
or college
OpenStudy (anonymous):
i am in biomedical engineering
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OpenStudy (anonymous):
actually going for it
OpenStudy (anonymous):
oh tats y
i know it now itself!!!!!!
derievation
i am just 6th
OpenStudy (anonymous):
good:)
OpenStudy (anonymous):
what a humble kid
OpenStudy (jamesj):
Alternatively, by the Work-Energy theorem)
(change in energy) = (work) = (Force).(displacement force applied)
\[\frac{1}{2} m v^2 - \frac{1}{2} m u^2 = F s = mas\]
Canceling m throughout and multiplying by 2
\[v^2 - u^2 = 2as\]