Question

The graph of y=3x^2+12x+19 is a parabola that opens in the direction ____. It has a vertex ____, y-intercept ____, and _____ real roots?

Answer 1

the leading coefficient always tells you the direction it is facing (up down)... therefore because the leading coefficient in this formula is positive 3, then you know that the parabola is facing upwards.

Answer 2

vertex can be calculated by first attaining the "x" coordinate with the formula \[(-b)/2a\] and then using that value to attain your "y" value. i,e, F(-b/(2a))

Answer 3

y intercept occurs when x=0, therefore solve the equation for when x=0... in this case it is 19

Answer 4

and to easily find your roots just use the quadratic formula (or search decomposition in wikipedia) quad formula is \[(-b \pm \sqrt{b ^{2}-4ac})\div2\]

Answer 5

**2a instead of 2.... so u should divide by 2x3=6