Question

find the vertex, line of symmetry and the max/min value and graph
f(x)=1/4(x+1)^2+3

Answer 1

this form\[y=a(x-h)^2+k\]has vertex (h,k); axis of symmetry x=h; if a>0 parabola opens upward and the value of the min is y=k; if a<0 then the parabola opens downward and the value of the max is y=y

Answer 2

do you want to try from here

Answer 3

btw, the LAST equation above is supposed to be y=k not y=y

Answer 4

Vertex (-1, 3)
Axis of symmetry x=-1
Vertex is a min since a=1/4 so y=3 is the value of the min
(see atached)