If x is a positive integer, what is one possible value of the units digit of 103^2x after it has been multiplied out?
\[103^2 x \ or \ 103^{2x}\]
isn't one possible answer 9? since the units digitis 3 and rewritten is 3^2 which equals 9....but there is more to it
a little experimentation will show you the pattern of the units digit. then you can figure out a reason why it must be true
2x will always be even so even power of 103 means 3 will be multiplied even no of times so possible values of unit digit can be 9 or 1
i am assuming the question is for \[103^{2n}\] in other words an even exponent
Hang on, I'm still waiting for the clarification. Which one of the two forms above is correct.
how did u get 9 and 1 Harkirat?
See if we take x = 1, then we get 103^2 = 10609 if we take x = 2, then we get 103^4 = 112550881 The unit digit will always result from the last digit 3^2x and will alternately be 9 and 1
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