Find an equation of the tangent line and normal line to the given curve at the specified point

y = (sqrt of x) / (x+1) at (4, 0.4)

Question

Find an equation of the tangent line and normal line to the given curve at the specified point

y = (sqrt of x) / (x+1)  at (4, 0.4)

anonymous · Answer

$$y=\sqrt{x} / (x+1 ) $$

jamesj · Answer

So first find the value of y'(4), that is the slope of the tangent.

jamesj · Answer

Hence what is dy/dx ?

anonymous · Answer

honestly, i really dont understand derivatives

jamesj · Answer

then you need to otherwise you can't do this problem.  This derivative is calculated using the quotient rule.

anonymous · Answer

i understand that the qoteitn rule is f'g - fg' / g^2

anonymous · Answer

then find dy/dx here and evaluate it at x = 4.

Then you have the slope of the tangent line as wel as a point and hence you can write down the equation of the line.

anonymous · Answer

how wud u find teh derivative of sqrt of x