Question

F(x)=1/sqrt(x-8)
How do you find the range?
I got the domain, x >8. If I plug back 8 in, I get undefined at the bottom.

Answer 1

range is infinti

Answer 2

when u plug in x=8 the function f(x)=1/0 anything divide by a very small number like 0 will result in inifinity

Answer 3

also range is from 0 to infinity it can't be less than 0 because there are no negative y values for this function because square root of a negative is imaginary

Answer 4

i think we're in the same class lol

Answer 5

lmaoo

Answer 6

unbreak did u understand the range?

Answer 7

But if you divide by a 0, you would end up getting undefined, so what you are saying is, if you get undefined, its infinity? The answer is actually (0,infinity) but when I graph it on my calculator, it stops at 1..which is weird

Answer 8

at x=1 or y=1?

Answer 9

at y=1

Answer 10

im confused, cause I saw a couple of videos online on how to find the domain and range. Most of them used easy examples, and they said find the domain and plug in the domain # for X.

Answer 11

ok i think some of what i told u was not right

Answer 12

But with mine, I end up getting 1/0 which I think you said is infinity..but how would I be able to tell if its -Infinity, or +infinity, or even (-infinity,+infinity)? In other words, how would I know the other point

Answer 13

so i am going to tell u it clearly now whats goin on with this function...this function does not exist for x<8 the reason being because when u plug in x<8 the denominator can not be solved because the square root of a negative number is imaginary and secondly when x does equal 8 this function the denominator goes to 0 then the calculator says it's undefined because it does to infinity and now y=1 at x=9 so i think u need to fix the domain on ur calculator to plot only x>8 and this function u can think of it as a square root function which does not start until x=8 so it can be thought of as delayed function because nothing happens before x=8

Answer 14

u can tell its positive infinity because its 1/0 at x=8 and the numerator is positive if the numerator was -1/0 then it would be negative inifinity

Answer 15

u get it?

Answer 16

yup

Answer 17

ty :D

Answer 18

range is y > 0.

Answer 19

range is [0,1]