Question

(1+x)^5

Answer 1

have u studied binomial theorem ?

Answer 2

thank u so much

Answer 3

u can also solve without using bionomial theorem
\[(1+x)(1+x)(1+x)(1+x)(1+x)=(1+x)^5\]
\[(1+x)^2(1+x)^2(1+x)=(1+x)^5\]
\[(1+x^2+2x)(1+x^2+2x)(1+x)=(1+x)^5\]
\[(1+x^2+2x)^2(1+x)=(1+x)^5\]
\[(1+x^4+4x^2+2x^2+4x^3+4x)(1+x)=(1+x)^5\]
\[(1+x^4+4x^2+2x^2+4x^3+4x)(1)+(1+x^4+4x^2+2x^2+4x^3+2x)(2x)=(1+x)^5\]
\[1+x^4+4x^2+2x^2+4x^3+4x+x+x^5+4x^3+2x^3+4x^4+4x^2)=(1+x)^5\]
\[1+5x^4+10x^3+10x^2+5x+x^5=(1+x)^5\]
\[x^5 + 5x^4+ 10x^3+10x^2+5x+1=(1+x)^5\]

Answer 4

it took a great time to solve sorry for the time taken but it is correct

Answer 5

nice answer :)