Question

8x(2x+4)=8

Answer 1

8x(2x+4)=8


16x^2+32x=8


16x^2+32x-8=0


8(2x^2+4x-1)=0


8(2x^2+4x-1)=0


2x^2+4x-1=0


Now use the quadratic formula to solve



x=(-b +- sqrt(b^2-4ac))/(2a)


x=(-4 +- sqrt(4^2-4(2)(-1)))/(2(2))


x=(-4 +- sqrt(24))/4


x=(-4 +- 2*sqrt(6))/4


x=(-2 +- sqrt(6))/2



So the solutions are \[\Large x = \frac{-2\pm\sqrt{6}}{2}\]

Answer 2

th last one is the answer

Answer 3

yep

Answer 4

it can be broken into

\[\Large x = \frac{-2+\sqrt{6}}{2} \ \text{or} \ x=\frac{-2-\sqrt{6}}{2}\]