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How many grams of copper metal are present in a 4.15g sample of copper(II) fluoride dihydrate?
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The chemical equation for copper (II) fluoride dihydrate is CuF2*2H2O, and from that, we can calculate a total weight of 137.5716 g/mol. From there, we can calculate the total molar presence of CuF by multiplying our total weight by the weight given by the problem which gives us X moles (the actual number is a decimal with almost 9 places so Im using X as a representative variable, the little x's are multiplication symbols.) The formal equation should look like this: X mol CuF*2H2O x (1 mol Cu/1 mol CuF*2H2O)x(63.546 g Cu/1 mol Cu) = 1.9169 g Cu. Adjust for significant figures as needed.
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