Mathematics
22 Online
OpenStudy (anonymous):
What is the solution set for |–2x + 8| = 12
Answer
x = 2 and x = 10
x = –2 and x = 10
x = –2 and x = –10
x = 2 and x = –10
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OpenStudy (amistre64):
what do you get when you plug in the options?
OpenStudy (anonymous):
its the first one right?
OpenStudy (amistre64):
i dont think it would be, but we can do better than just guess
OpenStudy (anonymous):
hmm
OpenStudy (amistre64):
what is -2 times 2?
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OpenStudy (anonymous):
-4
OpenStudy (amistre64):
and -4 + 8 = ?
OpenStudy (anonymous):
4
OpenStudy (amistre64):
would you say that |4| = 12 then ?
OpenStudy (anonymous):
no...
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OpenStudy (amistre64):
then x cannot equal 2
OpenStudy (amistre64):
lets try 10 :)
OpenStudy (amistre64):
what is -2 times 10?
OpenStudy (anonymous):
-20
OpenStudy (amistre64):
and -20 + 8 = ?
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OpenStudy (anonymous):
12
OpenStudy (amistre64):
well, -12 yes; does |-12| = 12 ?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
x = –2 and x = 10
OpenStudy (amistre64):
then we conclude that x does not equal 2; and it does equal 10
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OpenStudy (anonymous):
amistre can u stay here? im doing attest
OpenStudy (anonymous):
A test and I'm gonna need some more help
OpenStudy (amistre64):
hmmm ..... doing a test doesnt sound very ethical to me; I can help, but I want you to find the answers
OpenStudy (anonymous):
I knwo I just need you to help me figure out how to solve the problems and there is only 10 more questions
OpenStudy (amistre64):
lets do the next one then and see where it leads
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OpenStudy (anonymous):
What are the solution intervals for |x + 5| > 3?
Answer
x < –8 or x > –2
x > –8 or x < –2
x < 8 or x > –2
x > 8 or x < –2
OpenStudy (amistre64):
lets start out by seeing of x=0 is good or bad
OpenStudy (anonymous):
wouldnt it be good?
OpenStudy (amistre64):
when x=0 we get: |5|>3 is this a true or false result?
OpenStudy (anonymous):
true
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OpenStudy (amistre64):
it looks good to me; so we can narrow it down to between 2 numbers
OpenStudy (amistre64):
\[\cancel{x < –8 or x > –2}\]
x > –8 or x < –2
x < 8 or x > –2
\[\cancel{x > 8 or x < –2}\]
OpenStudy (amistre64):
lets try x = 7
OpenStudy (anonymous):
it works
OpenStudy (amistre64):
then this one looks to be the right area
x < 8 or x > –2
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OpenStudy (amistre64):
|dw:1318297269123:dw|
OpenStudy (anonymous):
Ok sweet~
here is the next one
On the graph of the equation 3x – 2y = –18, what is the value of the y-intercept?
Answer
6
–9
9
–6
OpenStudy (amistre64):
when x=0; what does y=?
OpenStudy (anonymous):
0?
OpenStudy (anonymous):
or 1?
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OpenStudy (amistre64):
i would say neither since 0 or 1 is not an option is it
OpenStudy (anonymous):
ugh this is confusing
OpenStudy (amistre64):
lets try it again:
when x = 0; y = ?
3x – 2y = –18
0
------------
0 -2y = -18
OpenStudy (anonymous):
-9?
OpenStudy (anonymous):
or actually its 9
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OpenStudy (amistre64):
close, but two negatives give a + result; id go 9 :)
OpenStudy (anonymous):
so the answer is 9 right?
OpenStudy (amistre64):
i would go with 9 yes
OpenStudy (anonymous):
What is the slope of the line which passes through (–6, 0) and (4, 0)?
Answer
0
–2
undefined
2
OpenStudy (anonymous):
dont you do like 0-0 and 4-(-6) or something liek that>
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OpenStudy (amistre64):
both your y values are the same; which means the no matter what you pick for x; you always have the same y value
OpenStudy (anonymous):
like y2-y1 and x2-x1