Question

Find the angle of intersection of the following pairs of curves:
y=2x,
x^5+ y^5=33

Answer 1

when i did the following:
x^5+(2x)^5=33
33x^5=33
x^5=1
x=1 => y=2(1)=2
intersection occurs at (1,2)
did you get this far?

Answer 2

yes..

Answer 3

myininaya pls help me after u done this

http://openstudy.com/groups/mathematics/updates/4e94435d0b8b7d552ae41420

sry for interupting

Answer 4

i wonder which angle you want
because you have 4 angles

Answer 5

the 4 angles that was created by the intersection

Answer 6

i know how to find the angle between two vectors ....

Answer 7

Actually the answer was 67.0 degress.. I just can't get the right solution..

Answer 8

maybe i should try converting to a polar equation

Answer 9

hmmm... let me see what happens

Answer 10

oh wait that might work...

Answer 11

so we have x=1 right?
this implies rcos(theta)=1

Answer 12

yup yup

Answer 13

but r=sqrt{x^2+y^2}=sqrt{1^2+2^2}=sqrt{1+4}=sqrt{5}

Answer 14

so we have
\[\cos(\theta)=\frac{1}{\sqrt{5}} => \theta=\cos^{-1}(\frac{1}{\sqrt{5}})\]

Answer 15

approzimately is 63.535 degrees

Answer 16

oops 63.435

Answer 17

i like my answer
it makes sense

Answer 18

Thank you.

Answer 19

its pretty close to 67 too

Answer 20

not too far off

Answer 21

yep.. i think i got it.. :)

Answer 22

cool

Answer 23

good question