Question

F(x)=(x+2)^2

Answer 1

what do you want to do here?

Answer 2

vertex

Answer 3

synmetry

Answer 4

f(x)= (x+2)(x+2)
f(x)= x^2+4x+4

Answer 5

y intercept is at 4

Answer 6

vertex of f(x) = a(x-h)^2+k is (h,k)


In the case of F(x)=(x+2)^2, h = -2 and k = 0


So the vertex is (-2,0)

Answer 7

axis of symmetry of f(x) = a(x-h)^2+k is x = h


In the case of F(x)=(x+2)^2, h = -2 and k = 0


So the axis of symmetry is x = -2