Question

if c^2^x-2c^x=8 then x = ? can anyone help please

Answer 1

gimmick is to write this as a quadratic equation in
\[c^x\] since
\[c^{2x}=(c^x)^2\]

Answer 2

i think i may have made a mistake
all the c's replace them with the letter e

Answer 3

in other words solve
\[z^2-2z-8=0\]
\[(z-4)(z+2)=0\]
\[z=4,z=-2\]

Answer 4

now replace
oh ok

Answer 5

\[e^x=4, e^x=-2\] and
\[e^x=-2\] is not possible since
\[e^x>0\] so only solve
\[e^x=4\] which in equivalent logarithmic form says
\[x=\ln(4)\]

Answer 6

oklay thanks youve been a great help :)