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Solve for y: x=ln(ln(lny))
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if x = ln y what is y? well, y = e^x So if x = Ln(ln y), what is y? and then what if x = ln(ln(ln y)) ?
Not sure I follow your logic. I was going to take e to both sides ie \[e ^{x}=e ^{\ln(\ln(lny))}\] \[e ^{x}=\ln(lny)\]
y = e^e^e^{ln(ln(ln(x))]
@jimmy: no, not right.
If x = ln y then take the exp of both sides: exp(x) = exp(ln(y)) = y i.e., y = e^x
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So if x = ln(ln(y)) take the exp of both sides once and see what you get. So now take it again.
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