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OpenStudy (anonymous):
a^m/a^n=a^m-n
OpenStudy (anonymous):
(6x)^6/(6x)^18
cancel out 6 (6x)'s from the top against the bottom to get
1/(6x)^12
OpenStudy (anonymous):
would 1/6x^3 be a right answer?
OpenStudy (anonymous):
i got that answer but i dont know if it is right
OpenStudy (anonymous):
that would be wrong, @lance has the answer
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OpenStudy (anonymous):
ok so it is 1/6x^12?
OpenStudy (anonymous):
or could i write it as 6x^12
OpenStudy (anonymous):
you can write it as 6^-12
OpenStudy (anonymous):
i knw with this math if it aint in the way they want it, it is wrong so its like you have different ways to write it but you have to take a chance on which one they are gonna accept lol
OpenStudy (anonymous):
well, ususally they alwasy ask write with positive exponents , which would make the answer
1/(6x)^12, if they as for negative exponents write it as (6x)^-12
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OpenStudy (anonymous):
yea it says positive. i just get confused on all of it. so it would be the first one
OpenStudy (anonymous):
yes it would
OpenStudy (anonymous):
thanks.
OpenStudy (anonymous):
anytime
OpenStudy (anonymous):
It helps to think of something like (6x)^3 as:
6x * 6x * 6x
so (6x)^3/(6x)^4 equals:
(6x * 6x * 6x) / ( 6x * 6x * 6x * 6x)
Then it's easy to see how they cancel out.