Question

f(x)=g(x)
f(x)=2x^2-x+1
g(x)=x^2-6x+8
Solve the Function.

Answer 1

There are 2 answers.

Answer 2

\[2x^2-x+1=x^2-6x+8\]\[x^2+5x-7=0\]now use the quadratic formula, which gives TWO answers for x because of the "plus or minus" part of the formula. You remember it, right?

Answer 3

\[x=(-b \pm \sqrt{b^2-4ac})/2a\]in this case we have
a=1
b=5
c=-7
plug in and solve!

Answer 4

I understand that but how did you get to that point. Can you show all of your work please?

Answer 5

I thought I did except I didn't first write

f(x)=g(x)

from there on it's what I have above:

2x^2-x+1=x^2-6x+8
x^2+5x-7=0

then quadratic and we're done.

Answer 6

oh i was plugging in one of those for x. i see what i was doing wrong. THANKS!

Answer 7

anytime!

Answer 8

:)