Find the roots. 3x-2=3/-2x.
First set the equation equal to f(x). The root of the function is where f(x) = 0.
Is the equation 3x-2 = 3/-2(x) or 3x-2 = 3/(-2x)?
The equation is 3x-2=(3/-2x). The number after the = sign is a fraction.
right but is -2x on the bottom of the fraction or is it 3/-2 * x
yes, -2x is on the bottom
ok so f(x) = -6x^2 +4x -3 so to find the roots solve for x when -6x^2 + 4x -3 = 0
alright, so now my question is how did you get the fraction to the other side of the eqution?
by multiplying everything by (-2x) (3x-2)(-2x) = (3/-2x)(-2x) which simplifies to -6x^2 + 4x = -6x/-2x which further simplifies -6x^2 + 4x = 3, then move the 3 over so you get -6x^2 + 4x - 3 = 0
if on the left side of teh equation the (-2x) is being distributed, why isn't the answer on the left side -6x/4x^2?
because (3x-2)(-2x) is the same as 3x(-2x) - 2(-2x) which is -6x^2 - (-4x) which is -6x^2 + 4x
oops im sorry i meant on the right side of the equation
ok, its (3/-2x)(-2x) which is the same as 3(-2x)(1/-2x) the (-2x)(1/-2x) cancels out leaving only the 3
im sorry im asking so many questions but where did you get the (1/-2x) from?
3/-2x is the same as (3/1)* (1/-2x)
ohh, okay that makes sense. thank you!
no problem, I would use the quadratic formula to find the roots
and luckily, that i remember how to do haha :)
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