The length of a rectangle is twice the width. The area is 162^2yd. Find the length and the width

Question

anonymous · Answer

I think:
2w^2=162^2
w^2=162*81
w=81sqrt(2)
l=162sqrt(2)

anonymous · Answer

your answer is correct CrazyEinstein.

anonymous · Answer

Thank you.

anonymous · Answer

CrazyEinstein and renanmit's conclusions are incorrect.

{ L = 2*w, L*w = 162 }
  L = 18 and w = 9
  L * w = 162

The length times the width using CrazyEinstein's answer is:$$162 \sqrt{2}*81 \sqrt{2}=26244 $$

stormfire1 · Answer

A = L*W
L = 2W
A = 2W * W
A = 2W^2
A/2 = W^2
81 = W^2
W = 9

and since the length is 2W, the length will be 18.

So the final equation would look like 162 = 18 * 9

anonymous · Answer

162^2yd means 162^2 or 162 ?
if it is 162^2, mine is right.
if it is 162, stormfire1's is right.

stormfire1 · Answer

Since it's an area, it's not 162^2....it's 162 square yards

stormfire1 · Answer

That's how I read it anyway

anonymous · Answer

Here is how WolframAlpha.com reads l=162sqrt(2) http://www.wolframalpha.com/input/?i=l%3D162sqrt%282%29

stormfire1 · Answer

I'd bet a lot of $ on the fact that she meant $$162 yd^2$$:)

anonymous · Answer

I agree.  That is how I interpreted the given area.

The go around regarding l=162sqrt(2) refers to @ CrazyEinstein's answer for the length.

anonymous · Answer

Haha, there is no need to bet. it is just a matter of clarification.