Tell me if I am right

The length of a rectangle is twice the width. The area is 162^2yds. Find the length and width

answer length 162, with 81

Question

Tell me if I am right

The length of a rectangle is twice the width. The area is 162^2yds. Find the length and width

answer length 162, with 81

anonymous · Answer

L=2W so L*W=2W*W=162 and$$2W^2=162$$$$W^2=81$$$$W=9$$and the length would be L=2W or L=2(9)=18.

check: 18*9=162 as it should

anonymous · Answer

im not sure I understand

anonymous · Answer

so the width is 9 and length is 18?

anonymous · Answer

yes; area=L*W and L=2W so area=(2W)*W or area=2W^2 in general and since area=162 we solve 
162=2W^2
after dividing by 2
81=W^2
square root both sides
9=W
this is the width; since the length is twice the width (L=2W) we have
L=2*9=18
this is the length

check: since area=L*W we can check by filling in the given (area=162) and found (W=9; L=18) values
162=9*18
162=162
indicating that these really are the dimensions