how do i find the derivative of (x+y)^2=x *y
We need more information. Are you taking the partial derivative with respect to x or with respect to y?
hmm it says find dy/dx
think its y
Implicit differentiation then. Result pending...
think its y
hey could u also help me with tan(X+y)=4x very much appreciated
Do you know how to do implicit differentiation? Make the equation equal to zero for a start. Expand the bracket and simplify. Then implicitly differentiate, remembering the x terms differentiate normally and any y terms get differentiated and multiplied by (dy/dx). You will need the product rule for the xy cross product.
oh k give me a min
i got X^2+2xy-xy=0
Sure thing. After those steps, you factor out the (dy/dx) term and solve for (dy/dx). You will get \[(dy/dx)=(y-2x)/(x+2y)\]
Yep, that is the first step. Notice how 2xy-xy = xy
ook getting it now
oh forgot y^2 above
2x+(x.dy/dx+y)+2y.dy/dx=0 is the implicitly derived solution, you just need to solve for dy/dx
hey when its tan (x+y)=4x what do i d with the tan?
Join our real-time social learning platform and learn together with your friends!