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How do you integrate this please?? dr/dt = 2r(1-r)
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nice job mimi
\[\frac{dr}{2r(1-r)} = dt\]\[\int\limits{\frac{dr}{2r(1-r)}} = \int\limits{dt}\]
[1/2r(1-r)]dr=dt =>integrating on both sides 1/2log r -1/2 log (1-r)=t
the first part by partial fractions \[\int\limits{dt} = t\]
Thanks guys!
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