Suppose the line tangent to the graph of f at x=3 is y=2x+1and suppose y=3x-3 is the line tangent to the graph of g at x=3. Find an equation of the tangent line to the following curves at x=3. a. f(x) + g(x) b. f(x) - 3g(x) c. 4f(x)
NEED HELP!
ok you know that \[f(3)=7,g(3)=6, f(3)+g(3)=13\]and you know that the slope will be 2 + 3 = 5 so you can use the point- slope formula to find the equation
its it clear how you know these things?
yess
ok then are you good from there? because the others work the same way. you know \[(f+g)'=f'+g'\] \[(f+g)'(3)=f'(3)+g'(3)=3+2=5\] and \[(f+g)(3)=6+7=13\] so use \[y-13=5(x-3)\] for your first answer
i think i might be good for the rest, thank you
i got 5x+3 for b but thats not right. could you show me the steps and the answesr cause im not sure what i did wrong
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