Question

graph of y=(2/3x)-2

Answer 1

http://go.hrw.com/math/midma/gradecontent/manipulatives/GraphCalc/graphCalc.html

Answer 2

in above link type (2/3x)-2

Answer 3

thanks

Answer 4

slope is (2/3) and y intercept is -2
Start at (0,2) and then go up 2 units and then right 3 units from (0,2)
then from (0,2) go down 2 units and then left 3 units.

Answer 5

how do i do the calculation to know how the graph will be,incase in eaxm

Answer 6

exams

Answer 7

You start with the y-intercept in this case it is -2, so you go down 2 units from the y-axis.
Using the slope because it is positive
you will travel up/right from that point and plot points
and then you will travel down/left from that point and plot points
On the exam you can create a table
use 0, 1, 2, -1, -2 for x values
calculate your y values
example x=0 y is -2 because y=(2/3)(0)-2 is -2 so you plot (0, -2)
continue with the other points
It is easier to plot it using point slope form. Remember b is for the point where you begin and m is for how you move from that point.

Answer 8

what of in this case f(x)=x^2-x-2

Answer 9

That is a quadratic. It is concave up and it crosses the y-axis at -2