induction question
\[\left(\begin{matrix}15 \\ 8\end{matrix}\right)\]
determine the value
\[\frac{15!}{8!(15-8)!}=\frac{15 \cdot 14 \cdot 13 \ \cdot 12 \cdot 11 \cdot 10 \cdot 9 \cdot 8!}{8! \cdot 7!}=\frac{15 \cdot 14 \cdot 13 \cdot 12 \cdot 11 \cdot 10 \cdot 9}{7!}\]
ty
no problem we can reduce the fraction more
so just multiply the top?
\[\frac{5 \cdot 3 \cdot 2 \cdot 7 \cdot 13 \cdot 4 \cdot 3 \cdot 11 \cdot 10 \cdot 9}{7 \cdot 6 \cdot 5 \cdot 4 \cdot 3 \cdot 2}\] \[=\frac{13 \cdot 3 \cdot 11 \cdot 10 \cdot 9}{6}=\frac{13 \cdot 11 \cdot 10 \cdot 9}{2}\]
yes now you just multiply the top
so how exactly do u break up 7!
14=2(7) there is 7 on bottom so the 7's cancel
so u went from 7! to 7 . 6 . 5 . 4 . 3 . 2
\[a!=a \cdot (a-1) \cdot (a-2) \cdot \cdot \cdot 3 \cdot 2 \cdot 1\]
kk tyvm
so the answer would be 6435
and also we could have divided top by 2 and bottom by 2 because 10=2(5) right?
\[13 \cdot 11 \cdot 5 \cdot 9\]
ok
yes 6435 is correct
ty :)
np
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