Hello,solve this please.
f(x) = x^2 - ax. Find a if the tangent of f's graph is parallel with (d):y=x-2011 at M(1,f(1)).
then found and the tangent's type.

Question

Hello,solve this please.
f(x) = x^2 - ax.  Find a if the tangent of f's graph is parallel with (d):y=x-2011 at M(1,f(1)).
then found and the tangent's type.

alfie · Answer

I'd start by thinking what is the geometric meaning of a derivative.

anonymous · Answer

yep

anonymous · Answer

f'(x) = 2x - a
this equals the gradient of a tangent at some point on the graph of f(x)
y = x - 2011 has a gradient of 1
so 2x-a = 1  so  a = 2x-1
can u continue from here?

anonymous · Answer

i think a must be 2011

anonymous · Answer

why the point (1,f(1)) is given then ?