l-3nl-2=4
lxl=-x only if x<0 thus after squaring we get 9n2=36 n2=36/9 n=-2 as lxl=-x will take negative value
It's almost the same thing here. Get rid of that -2, by adding 2 to both sides \[\left| -3n \right|=6\] Now, you know that -3n = -1*3n And, by properties of absolute values, |a*b|=|a|*|b|, \[\left| -1\right|\left| 3n \right|=6\] The absolute value of -1 is, of course, 1, so you can scratch it out since it's multiplying. And by the same property of abs. value, you can separate 3n \[\left| 3\right|\left| n \right|=6\] The absolute value of 3 is, of course, 3. Now divide by 3 on both sides, \[\left| n \right|=6/3\] \[\left| n \right|=2\] You can again do it analytically, n={-2,2} since the absolute values of those two numbers is 2, or you can square and take the square root \[\left| n \right|^2=4\] And since \[\left| x \right|^2=x^2\], You can get rid of that abs. value: \[n^2=4\] \[n=\pm \sqrt{4}\] \[n=\pm 2\]
thanks
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