Question

will the graph of y=(2x+3)/(x+1) have a vertical asymptote at x=-1?

Answer 1

yes, since distance between y and -1 approach zero as x approaches -1.

Answer 2

I should have said, since distance between y and x = -1 approach zero as x approaches -1.

Answer 3

how would i create a rational function under the following conditions? no vertical asymptote, no horizontal asymptote, and no x-intercept

Answer 4

approaching -1 does not mean that it ever reaches it. It never does since y is not defined at x = -1 (i.e. y = (2x + 3)/0 at this value)

Answer 5

y = 1 + |x|