Calculus1
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OpenStudy (anonymous):
linear congruence: complete soln:
4x(is equivalent to) 5(mod 21) @Mathematics

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OpenStudy (anonymous):
when I did the EEA I got 4(-5) + 21(1) = 1

OpenStudy (anonymous):
but then you have to mult by 5

OpenStudy (anonymous):
then x=xnot+bn/d

OpenStudy (anonymous):
when I multiplied by 5 I got 4(-25) + 21(5) = 5

OpenStudy (anonymous):
o ya then xnot is -25

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OpenStudy (anonymous):
x=-25+21n

OpenStudy (anonymous):
your way of writing things is different then how I did it

OpenStudy (anonymous):
you have to find all solutions

OpenStudy (anonymous):
yeah I got x is congruent to 17 (mod 21)

OpenStudy (anonymous):
k so where do i go from here

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OpenStudy (anonymous):
from the EEA you just convert it back into congruent form I think

OpenStudy (anonymous):
so x is congruent to -25 is congruent to what

OpenStudy (anonymous):
so 4(-25) congruent to 5 (mod 21)
so x congruent to -25 (mod 21/1) is the complete solution
and that is equivalent to x congruent to 17 (mod21/1

OpenStudy (anonymous):
since (-25) is some solution for x

OpenStudy (anonymous):
then you just put it into the Linear Congruence Theorem, V1

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OpenStudy (anonymous):
to get the complete solution

OpenStudy (anonymous):
o crap ok now i see it

OpenStudy (anonymous):
I don't know this stuff super well either lol

OpenStudy (anonymous):
did you show eea?

OpenStudy (anonymous):
yeah I put it in there

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OpenStudy (anonymous):
but theres no room

OpenStudy (anonymous):
the EEA for those were really short so I just wrote it in there tiny

OpenStudy (anonymous):
have you done any other problems on the assignment? I'm stuck on 5c lol

OpenStudy (anonymous):
only up to 3

OpenStudy (anonymous):
ok well I guess I might try asking on here again then

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OpenStudy (anonymous):
metoo

OpenStudy (anonymous):
4x(is equivalent to) 5(mod 21)
21 | 4x-5
21|4*(-4)-5
Hence -4 is a solution. ???
I am not sure.

OpenStudy (anonymous):
i dunno