Solve using the substitution method. Show your work. If the system has no solution or an infinite number of solutions, state this. -3x + y = 4 x + 3y = 22 Solve using the substitution method. Show your work. If the system has no solution or an infinite number of solutions, state this. -3x + y = 4 x + 3y = 22 @Mathematics

x = 1 y = 7

I don't get how you got that. I've done it like three times and got zero for the first equation and it doesn't sound right

I'll will show you how to solve it. Give me just a few minutes.

okay thank you

Solve one of the equations for either x or y. I chose to solve -3x + y = 4 for y. -3x + y = 4 -3x + 3x + y = 4 + 3x y = 4 + 3x Now you take the value of y which is y = 4 + 3x and substitute that into the other equation and solve for x, like so: x + 3y = 22 x + 3 (4 + 3x) = 22 x + 12 + 9x = 22 10x + 12 = 22 10x + 12 - 12 = 22 - 12 10x = 10 10x/10 = 10/10 x = 1 Now that you have the value for x you can solve for y in the other equation. -3x + y = 4 -3(1) + y = 4 -3 + y = 4 -3 + 3 + y = 4 + 3 y = 7 Now check the values of x and y by substituting them into both equations and seeing if they equal out. -3x + y = 4 -3(1) + 7 = 4 -3 + 7 = 4 4 = 4 x + 3y = 22 1 + 3 (7) = 22 1 + 21 = 22 22 = 22 The solution checks out. So your answer is x = 1 and y = 7

Okay see i had the steps right I just didn't have the one instead i was using a zero and getting myself confused thank you so much for the help

You are very welcome. :)

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