Question

Can someone explain me how to solve this? Given e^x y+y^2 x - sinx=6 Find dy/dx

Answer 1

go to tutor.com they can help you

Answer 2

implicit diff think of
\[y=f(x),y'=f'(x)\] and use the product, quotient and chain rule where applicable.

Answer 3

\[y+y^2x-\sin(x)=6\]
\[y'+2yy'x+y^2-\cos(x)=0\] in this case, the solve for y' with some algebra

Answer 4

your way smarter than me lol but im only in 8th grade

Answer 5

you get
\[y'+2yy'x=\cos(x)-y^2\]
\[y'=\frac{\cos(x)-y^2}{1+2xy}\]

Answer 6

thank you so much u saved my life!

Answer 7

yw

Answer 8

e^x was in the original problem, but you didn't have it in your answer