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Mathematics
OpenStudy (anonymous):

Differentiate (ln(f+g))

7 years ago
OpenStudy (jamesj):

This should now be easy for you, if you found the derivative of ln(fg). For the record \[ \frac{d \ }{dx} ln (f) = \frac{f'}{f} \]

7 years ago
OpenStudy (anonymous):

I understand ln(fg) = f'/f+g'/g, but what differently do I do here?

7 years ago
OpenStudy (jamesj):

so d/dx ln(u) = u'/u. Write here u = f + g. Then d/dx ln(u) = .... what?

7 years ago
OpenStudy (jamesj):

d/dx ln(u) = u'/u = ....

7 years ago
OpenStudy (anonymous):

f+g/f'+g'?

7 years ago
OpenStudy (jamesj):

careful

7 years ago
OpenStudy (anonymous):

Ooops lol. f'+g'/f+g

7 years ago
OpenStudy (jamesj):

d/dx ln(u) = u'/u = (f + g)' / (f + g) = ....

7 years ago
OpenStudy (jamesj):

yes

7 years ago
OpenStudy (anonymous):

Thanks a bunch. You officially have what I like to call Swag.

7 years ago
OpenStudy (jamesj):

Much obliged ;-)

7 years ago
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