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Differentiate (ln(f+g))
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This should now be easy for you, if you found the derivative of ln(fg). For the record \[ \frac{d \ }{dx} ln (f) = \frac{f'}{f} \]
I understand ln(fg) = f'/f+g'/g, but what differently do I do here?
so d/dx ln(u) = u'/u. Write here u = f + g. Then d/dx ln(u) = .... what?
d/dx ln(u) = u'/u = ....
f+g/f'+g'?
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careful
Ooops lol. f'+g'/f+g
d/dx ln(u) = u'/u = (f + g)' / (f + g) = ....
yes
Thanks a bunch. You officially have what I like to call Swag.
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Much obliged ;-)
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