i am looking to figure out ratios in geometry. If the angle of a trianle are in the extended ratio 1:3:5, find their measures
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OpenStudy (saifoo.khan):
x+3x+5 = 180.
OpenStudy (saifoo.khan):
Or,
\[\frac{x}{8} \times 180\]
OpenStudy (saifoo.khan):
where x is the ratio.
OpenStudy (anonymous):
ok - let me try that - give me a moment
OpenStudy (saifoo.khan):
Sure.
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OpenStudy (anonymous):
why isn't it 5x
OpenStudy (saifoo.khan):
typo.. sorry.
that's 5x/
OpenStudy (anonymous):
so it should be set up as x + 3x + 5x = 180
OpenStudy (saifoo.khan):
Yes.
OpenStudy (anonymous):
so then the next step is 4x + 5x = 180 and then it would be 9x = 180 and you divide it from there
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OpenStudy (saifoo.khan):
Correct.
u will get.
x = 20.
so the smallest angle is 20.
OpenStudy (anonymous):
so then you subtract that from 180 and get 160 for the other angles
OpenStudy (saifoo.khan):
No.
now.
u know the value of two other angles. that is 3x and 5x.
and you know the value of x for well.
so,
3(x) = 3(20) = ? degrees/
And
5(x) = 5(20) = ? degress
OpenStudy (anonymous):
so then i would get 60, 100, and 20.
OpenStudy (saifoo.khan):
Wow, you got them right. :D
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OpenStudy (anonymous):
:) thank you so much for ur help.
OpenStudy (saifoo.khan):
You welcome.
OpenStudy (anonymous):
do u have time to help me with a quadrilateral?
OpenStudy (saifoo.khan):
idk. i will see. if i can solve them for sure.
OpenStudy (anonymous):
alright. it has one angle of x+20, another of x-50, third one x+2, the last is x
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