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how would you factor this: t^3-3t+2? how would you factor this: t^3-3t+2? @Mathematics
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\[(t-1)(t-1) (t+2) \]
{t -> -2}, {t -> 1}, {t -> 1}
the book says the answer is (t-1)^2 (t+2), but how did you guys get it?
t^3 - 4t + t + 2 => t*(t^2-4) +1(t+2) => t*(t-2)*(t+2) +1*(t+2) => (t-1)(t-1)(t+2)
wait that doesn't make sense ^ (sheg) how did you get (t-1)(t-1)(t+2) if you have t*(t-2)*(t+2) +1*(t+2)
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t(t-2)(t+2)+(t+2) =>(t+2)[t(t-2)+1] =>(t+2)(t^2-2t+1) and (t^2-2t+1)=(t-1)^2 =>(t+2)(t-1)^2
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