Mathematics 100 Online
OpenStudy (anonymous):

Can someone explain why the following is correct for n=1:

OpenStudy (anonymous):

$\sum_{k=2}^{2n+1} 1/k(k+1) = n/2(n+1)$

OpenStudy (anonymous):

For $$n=1$$, we have $$\sum_{k=2}^{3}\frac{1}{k(k+1)}=\frac{1}{2(3)}+\frac{1}{3(4)}=\frac{2+1}{3(4)}=\frac{1}{4}=\frac{n}{2(n+1)} \text{ (since n=1)}$$.

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