Mathematics OpenStudy (aravindg):

if x=a(cos t +log tan1/2 t) and y=a sin t ,show that dy/dx=tan t @Physics OpenStudy (anonymous):

is log = ln or log base 10? OpenStudy (aravindg):

ln OpenStudy (anonymous): OpenStudy (anonymous):

plz click on that and help me? OpenStudy (aravindg):

dont post ur qn here OpenStudy (anonymous):

Ok then. $x=a(cost+\ln(\tan(t/2)) \rightarrow dx/dt=a(-sint+0.5\sec^2(t/2)/\tan(t/2))$$y=asint \rightarrow dy/dt=acost$ OpenStudy (anonymous):

what an ugly mess, but i guess that is what you have to do $\frac{dy}{dx}=\frac{dy}{dt}\frac{dt}{dx}$ OpenStudy (anonymous):

Sorry about the delay, was just re-checking my work. OpenStudy (anonymous):

$a(-sint+0.5\sec^2(t/2)/\tan(t/2)) = a(-sint+\sec(t/2)/2\sin(t/2))$$=a(-sint+1/2\cos(t/2)\sin(t/2))$ [Double angle formula for sin]$=a(-sint+1/sint)$$this \implies dy/dx = cost/(-sint+1/sint) = sintcost/(1-\sin^2 t)$$1-\sin^2 t = \cos^2t \therefore dy/dx = sintcost/\cos^2 t = sint/cost=tant$ Q.E.D.

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