Mathematics 79 Online OpenStudy (anonymous):

Find the critical numbers of the function on the interval 0 ≤ θ < 2π. f(θ) = 2cos(θ) + (sin(θ))^2?? OpenStudy (anonymous):

To find critical numbers you want to take the derivative and set it equal to 0. f(θ) = 2cos(θ) + (sin(θ))^2 f '(θ) = -2sin(θ) + 2sin(θ)cos(θ) OpenStudy (anonymous):

by critical number you mean the angle? OpenStudy (anonymous):

yea it is just cos and sin is what gets me. they confuse me. OpenStudy (turingtest):

critical numbers are where f'(x) is either 0 or undefined, so first we need the derivative using the chain rule: f'(x)=-2sinx+2sinx(cosx)=0 cosx=1 x=2(pi)n where n=0,1,2,... OpenStudy (anonymous):

0 = -2sin(θ) + 2sin(θ)cos(θ) 0 = 2sin(θ)(-1 + cos(θ)) So you either want cos(θ) = 1 or sin(θ)=0 OpenStudy (anonymous):

cos(θ) = 1 at θ = π/2 or sin(θ)=0 at θ = 0, π The critical values should be 0, π/2, and π

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